1.Three ants are sitting at the three corners of an equilateral triangle. Each ant starts randomly picks a direction and starts to move along the edge of the triangle. What is the probability that none of the ants collide?
Solution:-
So let’s think this through. The ants can only avoid a collision if they all decide to move in the same direction (either clockwise or anti-clockwise). If the ants do not pick the same direction, there will definitely be a collision. Each ant has the option to either move clockwise or anti-clockwise. There is a one in two chance that an ant decides to pick a particular direction. Using simple probability calculations, we can determine the probability of no collision.
P(No collision) = P(All ants go in a clockwise direction) + P( All ants go in an anti-clockwise direction) = 0.5 * 0.5 * 0.5 + 0.5 * 0.5 * 0.5 = 0.25
A simple way to solve.
- Each ant has 2 possibilities of moving in a direction.. clockwise or anti-clockwise. Now as there are 3 ants .. we have 8 total possibilities of the ants moving in a direction.
Now out of 8 we can have only 2 possibilities where they will not collide.
i.e if all the ants travel clockwise or all the ants travel anti-clockwise.
i.e if all the ants travel clockwise or all the ants travel anti-clockwise.
so the probability is 2/8 = 1/4 = 0.25
- P(#collision)= #of way when there is no collision/ total number of way ants can move
= 2/2^3
= 1/4
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